Le+math+problemmm



WOOOO! CONGRATS ALEXIA! The correct answer is: 1.

The work:

So, as I said, you need to factor. Forget about dividing for now.

4x^2+ 11x + 6 The factors of 4 are 4 and 1 and 2 and 2. The factors of 6 are 6 and 1 and 2 and 3. Let's try using 3,2 and 1,4.

(4x + 3 ) ( x+ 2 )

The above equals 4x^2 plus 8x plus 3x plus 6. Combine like terms and you get 4x^2+11x+6.

You factor the other numerators and denominators just like so.

You end up with: __(4x+3)(x+2)__ divided by __(4x+3) (x-4)__ (x+2) (x-7) (x-7) (x-4)

Bam. Multiply by the reciprocal, yeah?

__ (4x+3) (x+2)__ X (__x-7) (x-4)__ (x+2) (x-7) (4x+3) (x-4)

WOOOULD YOU LOOK AT THAT. You can cross out the terms that are the same since you're multiplying. Or, you multiply this whole thing which would defeat the whole purpose.

__ (4x+3 ) (x+2) __ X ( __ x-7)  (x-4) __ (x+2) (x-7) (4x+3) (x-4)

And now you look at the top and bottom. THEY'RE THE SAME! OMG!

Crossss em out. __ (4x+3 ) (x+2) __X ( __ x-7) (x-4) __ (x+2) (x-7) (4x+3) (x-4)

OH MAN. EVERYTHING'S CROSSED OUT.

Does this mean the answer is zero? No. It just means that the problem is now 1 times 1- you were just REDUCING the fractions. So, one times one is

__**ONE.**__
__**Thank you to Emma, Lauren, and Luke for attempting to solve the aforementioned problem! More will be up soon ;)**__  __**In faaaact: Here's one: Le riddle!**__